The Little MAC Attack
dankaminsky.com/2015/05/07/the-little-mac-attack
THIS IS NOT A BREAK OF HMAC. THIS IS NOT A BREAK OF HMAC. THIS IS NOT A BREAK OF HMAC. That being said: Let bz=blocksize(h), k=a[0:bz]^(0x36*bz): If h(a)==h(b) and a[0:bz]==b[0:bz], then hmac(k, ...
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